i know my f1 snakes from a bloodred motley and a lavender motley would give me all the outcomes. for example it would give me 42 percent normals, 66 poss het for bloodred, 66 percent het for levender, and 66percent het for motley. now is that telling me that 66 percent will give me either of them,or does it mean only 66 percent carry that gene. or do they all carry the gene but only 66 percent of the 42 percent will show. I dont know if that made any sense.
Well the others have already stated that you will get 100% motley het blood lavs so I won't go in to that...
But for future reference...when you do get pairings that will result in %'s.
Say you did an amel het anery x amel het anery.
The true results would be 50% amel het anery....25% snow....25% amel
However, the visual results would be 75% amel with a 66% possible het anery...and 25% snows. This is because het's cannot be seen, so you would not know whether you had an amel het anery, or an amel no hets.
This is how the 66% is derived from that crossing.
If you do a punnet square for het anery x het anery (I'm ignoring the amel because both parents are homo amel so all offspring will be homo amel). I will use A and a for this example to represent the anery gene (Aa = heterozygous).
Punnet square for Aa x Aa will result in (AA, Aa, Aa, aa)
aa will be homo for anery so you are left with AA, Aa, and Aa....all of which will appear amel...but like I said you won't know if it's het (Aa) or not (AA) because you cannot visualize hets. Therefore, you have 2 out of 3 chance (i.e. 66% possibility) that it will be heterozygous....and a 33% possibility that it will not.