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f2

henry2009

New member
i know my f1 snakes from a bloodred motley and a lavender motley would give me all the outcomes. for example it would give me 42 percent normals, 66 poss het for bloodred, 66 percent het for levender, and 66percent het for motley. now is that telling me that 66 percent will give me either of them,or does it mean only 66 percent carry that gene. or do they all carry the gene but only 66 percent of the 42 percent will show. I dont know if that made any sense.
 
your right i put in the wrong info. I did a new one. It told me i would get a 6 percent chance of a plasma motley does anyone ever see one of them. Also how much are those worth
 
Hi,

If you bred a lavender motley to a bloodred motley you will ONLY get Motleys het Lavender Bloodred. ALL of the hatchlings would be Motleys het Lavender Bloodred.


If you bred a pair of Motleys het Lavender Bloodred together you would get:
9/16 Motley (66% poss. het. Lavender, 66% poss. het. Diffused)
3/16 Motley, Lavender (66% poss. het. Diffused)
3/16 Motley, Diffused (66% poss. het. Lavender)
1/16 Motley, Lavender, Diffused
 
i know my f1 snakes from a bloodred motley and a lavender motley would give me all the outcomes. for example it would give me 42 percent normals, 66 poss het for bloodred, 66 percent het for levender, and 66percent het for motley. now is that telling me that 66 percent will give me either of them,or does it mean only 66 percent carry that gene. or do they all carry the gene but only 66 percent of the 42 percent will show. I dont know if that made any sense.

Well the others have already stated that you will get 100% motley het blood lavs so I won't go in to that...

But for future reference...when you do get pairings that will result in %'s.

Say you did an amel het anery x amel het anery.

The true results would be 50% amel het anery....25% snow....25% amel

However, the visual results would be 75% amel with a 66% possible het anery...and 25% snows. This is because het's cannot be seen, so you would not know whether you had an amel het anery, or an amel no hets.

This is how the 66% is derived from that crossing.
If you do a punnet square for het anery x het anery (I'm ignoring the amel because both parents are homo amel so all offspring will be homo amel). I will use A and a for this example to represent the anery gene (Aa = heterozygous).

Punnet square for Aa x Aa will result in (AA, Aa, Aa, aa)
aa will be homo for anery so you are left with AA, Aa, and Aa....all of which will appear amel...but like I said you won't know if it's het (Aa) or not (AA) because you cannot visualize hets. Therefore, you have 2 out of 3 chance (i.e. 66% possibility) that it will be heterozygous....and a 33% possibility that it will not.
 
Ok if thats the case There is no way of knowing which ones to hold back to get desired f3's. I would have to hold them all back and breed correct until i can prove them out,and even then they may carry the gene but doesnt show up on the f3's. How would i go about choosen which ones to breed.
 
F1's

It looks like everyone is missing your question. You all ready have F1's from that pair, correct? So all of your F1's are motley het for lavender and bloodred. Therefore, when you breed a pair of these together, you should get all motleys, and 1/16 will be a plasma motley. the other percentages you will have to figure out, but bottom line is 1/16 is plasma motley, you will also get some lav mots and blood red mots and some plain mots. Hope that helps. If that is not quite enough details, let me know. Others can help now, too, since I think this is closer to what you are asking, Brad Lichtenhan

i know my f1 snakes from a bloodred motley and a lavender motley would give me all the outcomes. for example it would give me 42 percent normals, 66 poss het for bloodred, 66 percent het for levender, and 66percent het for motley. now is that telling me that 66 percent will give me either of them,or does it mean only 66 percent carry that gene. or do they all carry the gene but only 66 percent of the 42 percent will show. I dont know if that made any sense.
 
It looks like everyone is missing your question. You all ready have F1's from that pair, correct? So all of your F1's are motley het for lavender and bloodred.

You know what, now that I read it over I think you are correct. It was worded kind of odd that I missed what it was saying.

i know my f1 snakes from a bloodred motley and a lavender motley would give me all the outcomes. for example it would give me 42 percent normals, 66 poss het for bloodred, 66 percent het for levender, and 66percent het for motley. now is that telling me that 66 percent will give me either of them,or does it mean only 66 percent carry that gene. or do they all carry the gene but only 66 percent of the 42 percent will show. I dont know if that made any sense.

Parents: bloodred motley x lavender motley
f1: 100% motley het lavender bloodred
crossing: motley het lav blood x motley het lav blood
f2:
56.25% (9/16) motley ph lav ph blood
18.75% (3/16) motley blood ph lav
18.75% (3/16) lavender motley ph blood
6.25% (1/16) lavender motley bloodred

Is this right?/what you're looking for?

And if I'm not mistaken I believe all poss hets will be 66% poss. (meaning there is a 66% chance that the snake could carry that gene in a heterozygous (Aa) form)
 
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