diver19 said:
what would this produce
anery motley x ghost
anery motley x amelinistic
will the motley pattern appear on the offsprings
tnx a lot.. just a newbie havent got a hang of genetics yet
Motley is recessive to "not Motley" so crossing a motley to a not-motley (who does not carry motley) will produce not-motleys who carry motley ("het motley").
Well, an Anery Motley is (homozygous anery, homozygous motley - assuming that the motley is a motley and not visual motley het stripe)
A Ghost is (homozygous anery, homozygous hypo).
Neither of those parents can give anything BUT "anery" to their offspring, so 100% of the babies will be Anery. The Anery Motley can't give anything BUT motley to its babies, so the babies will be het for motley - they'll carry it but not show it. The Ghost can't give anything BUT hypo to its babies, so the babies will be het for hypo. Therefore, you'd expect:
100% Anery het Motley, het Hypo
And your Anery Motley cross Amelanistic, if they have no other hets, will produce:
100% visual normal, het Amelanistic, het anerythristic, het motley (aka "het Snow Motley")